Question

Write the equation of the line perpendicular to the line x - 5y = -10 and passing through the point (2,5).

Answer 1

So you know the gradient that you are looking for is (was it -5?)
the equation you then form is y = mx+b
in this case m = -5
so sub x = 2 and y = 5 to the equation to find b and re-write the answer.

Answer 2

first find the slope of the given line
slope of the given line =- (coefficient of x)/(coefficient of y) = m (say)
then the slope of the line perpendicular to the given is given by -1/m
now eqyuation of line with slope m1 and passing throughx1,y1
is given by
y-y1= m1 (x-x1)

Answer 3

here slope of the given line =1/5
hnce slope of the line perpendicular to it is given by -5
and since the line passes through 2,5
and hence the reqd line
is
(y-5) = -5 (x-2)

Answer 4

y = 2x ?

Answer 5

You set the problem in slope-intercept form: y=mx+b. Then you take the slope, m, and make it into the negative reciprocal. With that, use the formula, y-y1=m2(x-x1), and plug in the two points for y1 and x1. Then plug in the new slope, and distribute it, then solve for y. You should get y=-5x+5, and I'm not sure whether or not you need to find b.

Answer 6

these are the questions
Write the equation of the line parallel to the line 10x - 5y = 8 and passing through the point (2,4).

Write the equation of the line parallel to the line 4x + y = -1 and passing through the point (5,0).

Write the equation of the line perpendicular to the line x - 5y = -10 and passing through the point (2,5).

Write the equation of the line perpendicular to the line x - 3y = 9 and passing through the point (3,5).

Write the equation of the line parallel to the line 4x + 2y = 5 and passing through the point (-3,5).


and these are the answers
A) y = -2x - 1
B) y = -3x + 14
C) y = 2x
D) y = -5x + 15
E) y = -4x + 20