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At the time t = 0 the velocity of an object is u and at time t its acceleration f = at. Then the velocity at time t will be A) u B) at C) u + at^2 D) u + ½ at^2
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\[\frac{ dv(t) }{ dt }=at \rightarrow v(t)=\int\limits_{?}^{?}atdt=\frac{ 1 }{ 2 }at^2+C\] \[v(0)=u=C \rightarrow v(t)=u+\frac{ 1 }{ 2 }at^2\]
how did u get\[dv(t)\div dt=at\]
Because it says acceleration at time t is "at" and we know acceleration is the derivative of velocity vs time
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