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Mathematics 10 Online
OpenStudy (anonymous):

True or False In a quadratic function written in the vertex form y= a (x-h)^2+k, an increase in the value of h move the parabola to the right of the cartesian plane

OpenStudy (anonymous):

remember (h, k) is the vertex|dw:1377953381410:dw|

OpenStudy (anonymous):

tell me if I am not clear with an "@" thing

OpenStudy (anonymous):

i dont get it

OpenStudy (anonymous):

one second.

OpenStudy (anonymous):

|dw:1377953574585:dw|

OpenStudy (anonymous):

sorry you can't read that, I will write those words down here.

OpenStudy (anonymous):

|dw:1377953706591:dw|

OpenStudy (anonymous):

I'm thinking that its false right?

OpenStudy (debbieg):

Compare: \(y=x^2\) (h=0) to \(y=(x-1)^2\) (h=1) What happens to the position of the parabola in the plane?

OpenStudy (debbieg):

Remember what h is: it is the x-coordinate of the vertex. So if you increase that and don't change anything else, what happens to the parabola?

OpenStudy (anonymous):

the parabola goes upward

OpenStudy (debbieg):

if you increase the \(\Huge \color{red} {\text{x-coordinate}}\) of the vertex????

OpenStudy (debbieg):

Where is the point (0,0) vs. the point (5,0)?

OpenStudy (anonymous):

the parabola would go downward @DebbieG right?

OpenStudy (debbieg):

Where is the point (5,0) compared to the point (0,0)? Is (5,0) directly above, below, to the right or to the left of (0,0)?

OpenStudy (anonymous):

to the right

OpenStudy (anonymous):

im confuse

OpenStudy (debbieg):

ok, GOOD. So when you increase the x-coordinate of a point, that point moves to the right. Now apply that to your problem. Do you know how to get the coordinates of the vertex, from the vertex form? If \(\Large y= a (x-h)^2+k\) then WHAT is the vertex?

OpenStudy (debbieg):

if \(\Large y= (x-1)^2+3\) then what is the vertex?

OpenStudy (anonymous):

yes i know how to get the coordinates

OpenStudy (debbieg):

OK, then what happens if you INCREASE h?

OpenStudy (debbieg):

What is the vertex of: \(\Large y= (x-1)^2+3\) vs. What is the vertex of: \(\Large y= (x-2)^2+3\) In the 2nd one, I've INCREASED h from 1 to 2. What happened to the vertex? where did it go?

OpenStudy (anonymous):

1,3 is the coordinates

OpenStudy (anonymous):

it also increases its value

OpenStudy (debbieg):

I don't know what "it also increases its value" means. A vertex doesn't have a "value". It's coordinates do. So the question I'm asking is, what HAPPENS to the vertex, e.g., where does it go, as I increased h from 1 to 2..... did the vertex (and hence, the graph of the parabola) move to the right, the left, up or down?

OpenStudy (anonymous):

to the right

OpenStudy (debbieg):

You are correct that (1, 3) is the vertex in the first equation. What is the vertex in the 2nd equation? and where is that point, relative to (1, 3)? CORRECT. So an increase in h, moved the parabola...... to the right! :)

OpenStudy (anonymous):

so the answer is true?

OpenStudy (debbieg):

What do you think? :)

OpenStudy (debbieg):

We just showed that, didn't we? ;)

OpenStudy (anonymous):

thanks

OpenStudy (debbieg):

You're welcome. :)

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