Solve (x - 2 < 5) U (x + 7 > 6). {x | -1 < x < 7} {all real numbers} Ø i got A
Looks good. :)
oh wait stop.
NOPE. sorry.
You want the UNION, so you want EVERYTHING that is in EITHER SET. think about what's in each set, and then what you get if you take all that is EITHER SET.
Look ! What the numbers can you get from (x - 2 < 5) ?
yooohooo... @dirtydan667
x>=4
From x - 2 < 5 ? add 2 to both sides.
and then for x + 7 > 6 subtract 7 from both sides. what's the solution there?
Since this is a union, you want: all x's that are in the FIRST set OR the SECOND set (or both)
No let see : 6-2<5 5-2<5 4-2<5 ... You can give 6>= Ok ? Do you understand ?
sorry guys i went to the bathroom lets continue so subtract seven i get x>-1
i think its 0/ guys @E.ali and @DebbieG
what did you get for the first one? From x - 2 < 5 ? add 2 to both sides. x>-1 is correct but I haven't seen you answer the first one correctly.
oh nvm all real numbers
X-4<7
@DebbieG
Yes, all reals. :) In general, if you take a union of 2 sets, one going to -inf and the other to +inf and they overlap in the middle, then you will get all real numbers. :)
thanks for explaing it more out
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