Question

help me

Answer 1

\[\int\limits \cos ^2x \div \cos ^2x+4\sin ^2x dx\]

Answer 2

so 1+4sin^2(x)?

Answer 3

any one to help me

Answer 4

denominator has (cos^2x+4sin^2x)?

Answer 5

yes

Answer 6

sin^2x=(1-cosx)/2
cos^2x=(1+cosx)/2 replace and solve

Answer 7

wait i do

Answer 8

is cos^2x=(cos2x+1)/2 not (1+cosx)/2

Answer 9

sry its i was wrong replace x by 2x and 2x by x in lhs and rhs respectively

Answer 10

we get \[\int\limits ( \cos2x+1)/5\cos2x-3\]

Answer 11

so cn u help me how to finish t?