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OpenStudy (highschoolmom2010):
whats where im lost
terenzreignz (terenzreignz):
^_^
You're actually doing great :)
Now, 17 cancels out here:
\[\frac{ 14 \sin 80 }{ 17 }=\frac{ \cancel{17} \sin Z }{ \cancel{17} }\]
terenzreignz (terenzreignz):
and we get...
\[\Large \sin Z = \frac{14\sin 80^o}{17}\]
OpenStudy (highschoolmom2010):
but i plugged the remaining in calculator and got a crazy answer
terenzreignz (terenzreignz):
What was it? ^_^
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OpenStudy (highschoolmom2010):
0.81101814953
OpenStudy (highschoolmom2010):
that cant be right
terenzreignz (terenzreignz):
Ahh... I see.
Because what you got was the SINE of the angle Z :)
You have to run it through \(\large \sin^{-1}\) to get the angle Z itself ^_^
\[\Large Z = \sin^{-1}\left(\frac{14\sin 80^o}{17}\right)\]
OpenStudy (highschoolmom2010):
oh i forgot to do teh inverse
terenzreignz (terenzreignz):
There's your problem ^_^
I trust it no longer IS a problem? :D
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OpenStudy (highschoolmom2010):
let me try that and see what i get '
terenzreignz (terenzreignz):
I'm sure it'll be more... believable... this time around ^_^
OpenStudy (highschoolmom2010):
54.1955269839
terenzreignz (terenzreignz):
More reasonable, don't you think? ^_^
terenzreignz (terenzreignz):
Correct, by the way :D
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