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If h(2)=9 and h'(2)=-2, find the following
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\[\frac{ d }{ dx }(\frac{ h(x) }{ x })\]
X=2
so what i thought is that since h(2)=9, they want the derivative of 9/2 which is zero
apparently thats not the case
use the quotient rule: \[\frac{ d }{ dx }\left( \frac{ f(x) }{ g(x) } \right)= \frac{ f'(x)g(x) - f(x)g'(x) }{ (g'(x))^2 }\]
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I also did that and didnt check my work lol i thought i divided by zero
hehe lol
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