Question

The incidence of cystic fibrosis, a recessive genetic disorder in the Caucasian population of United States, is 1 in every 2,500 individuals. Find the number of heterozygous carriers.
(p + q = 1, p2 + 2pq + q2 = 1)

A:0.0392
B:0.0254
C:0.045

Answer 1

To solve for heterozygous, you know that
p = dominant
q = recessive

so 2pq, must be heterozygous.

You already know, given by the information, that you have recessive, so q\(^2\) = \(\frac{1}{2500}\),
solve for q, when p + q = 1

q = \(\sqrt{\frac{1}{2500}}\)
p = 1-q
p = ?

But you don't know your entire population. So you will just leave it as "x"

Answer 2

You want 2pq. Remember.

Answer 3

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Answer 4

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