Am I doing this right? Suppose you roll an eight-sided die two times hoping to get two numbers whose sum is greater than 10. What is the sample space? How many favorable outcomes are there?

Question

anonymous · Answer

so far my work is:
8 x 8 = 64

p(event) = number of favorable outcomes/total possible outcomes

we have 21 possible outcomes that would equal ten:

3+8, 4+7, 4+8, 5+6, 5+7, 5+8, 6+5, 6+6, 6+7, 6+8, 7+4, 7+5, 7+6, 7+7, 7+8, 8+3, 8+4, 8+5, 8+6, 8+7, 8+8

so 21/64 x 100 = 32.8125

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i'm not sure if i'm getting my answer properly.

cwrw238 · Answer

looks good

anonymous · Answer

oh ok

anonymous · Answer

i hope so

phi · Answer

Yes, that  is correct, but 
1) you have a typo.  You have "that would equal ten:"  and mean "greater than ten"

2)  The question did not ask for the probability, just the number of favorable outcomes.  So you did extra work  (unless they ask later on)

phi · Answer

You could (tho it is tedious)   draw an 8 x 8 matrix and label the columns and rows 1 through 8
then color in the favorable squares  (where the row +column > 10)

anonymous · Answer

thank you for pointing out the typo good eye