Question

Help? :)

Answer 1

What is the simplified form of \[\frac{ x ^{2-64} }{ x ^{2}-16x+64 }\]

Answer 2

is the -64 part of the exponent notation in the numerator?

Answer 3

make factors of the numerators and denominators and cancel the common factor

Answer 4

The numerator can be factored.

So we need to factor it: what two numbers when multiplied give you +64 but when added it gives you -16?

Answer 5

8+8=16

Answer 6

I have a feeling the problem is like this:
\[\frac{ x^2 - 64 }{ x^2 - 16x + 64 }\]

Am I right @Sav_1012 ??

Answer 7

@surjithayer no that is wrong.

Answer 8

no thats right

Answer 9

sorry!

Answer 10

2-64 makes=-62 that makes no sense

Answer 11

So we need two numbers that when multiplied they give you + 64.
So:
1 * 64 = 64
8 * 8 = 64
-8 * -8 = 64



these are our two best options we can work with right now.
8 * 8 = 64
-8 * -8 = 64

Now we need to check if any of those when added give us -16.
8 + 8 = 16
-8 + -8 = -16

So we see that -8 and -8 work!

\[\frac{ x^2 - 64 }{ x^2 - 16x + 64 } \rightarrow \frac{ x^2 - 64}{ (x - 8 (x-8)}\]

Answer 12

* (x - 8) (x - 8)

forgot the parenthesis

Answer 13

Now we need to factor the numerator since we already factored the denominator.

Answer 14

Any ideas on how to do that? @Sav_1012 ??

Answer 15

nope. Im having to finish this course that i took freshamn year and i forgot how to do all this

Answer 16

Did you understand how i factored the denominator??

Answer 17

i just forgot how to do all of it. to be honest

Answer 18

But did you "remember" how to do it now? What I mean is did you kinda remember how to factor the denominator as how i did it?

Answer 19

idk

Answer 20

Take a look at the numerator:
x^2 - 64

x^2 - a^2 ---> (x + a)(x - a)

So how would you factor x^2 - 64?

Answer 21

If you do now want to try, and give it a try, then sorry but I can not force you so good luck.
You got to be willing to learn and be patient and TRY.