how many atoms are in .20 moles of lead

Question

abb0t · Answer

0.2 moles $\times$ $\frac{atom}{6.022 \times 10^{23}mol}$ = atoms of Lead

anonymous · Answer

@abb0t  SorRy didn't gt it..

abb0t · Answer

Don't get what?

anonymous · Answer

0.2 moles $\times$ $\frac{atom}{6.022 \times 10^{23}mol}$ = atoms of Lead

anonymous · Answer

???

anonymous · Answer

hmm....

theeric · Answer

$1\ mol\ of\ atoms\approx 6.022\times 10^{23}\ atoms\\implies1=\dfrac{6.022\times 10^{23}\ atoms}{1\ mol\ of\ atoms}$

@abbot , isn't that the conversion factor?

So if you have $0.20\ mol\ of\ lead\ atoms$, you multiply it by $1$, the conversion factor.
$0.20\ mol\ of\ lead\ atoms\times\dfrac{6.022\times 10^{23}\ atoms}{1\ mol\ of\ atoms}\huge\longrightarrow\normalsize atoms\ of\ lead$

@Khiz , is this what you were thinking?

ookawaiioo · Answer

@theEric is right. 

abbot and khiz got them mixed around.

theeric · Answer

Alright! I think @KhiZ was confused by @abbot 's response, and posted abbot's equation as part of a question.

theeric · Answer

Thanks for checking, too, @oOKawaiiOo ! :)

ookawaiioo · Answer

np!

goformit100 · Answer

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anonymous · Answer

Thanx @theEric :)
Thatx exactly wht i ws thnking..

theeric · Answer

Cool! :) Glad we got that settled, then. :)

anonymous · Answer

yupx :)