Question

Help?

Answer 1

What are the solutions for x in the proportion\[\frac{ 4x-3 }{ x }=\frac{ 2x }{ 2 }\]

Answer 2

What I would personally do is try to get rid of the denominators, make sure they are not fractions. Now if you had something like x - 3 = 8, you have a subtraction of 3 and you do the opposite to solve for x, add 3 to both sides. Except in this case you have division, which means we reverse the process by multiplication, which in turn would get rid of the fractions. Here's an example of the first fraction. Say I want that x out of the denominator. I would simply multiply everything by x like so:

\[(x)\frac{ 4x-3 }{ x }=(x)\frac{ 2x }{ 2 }\]becomes:
\[4x-3 = \frac{ 2x ^{2} }{ 2 } \]From here, you can get that 2 out of the second denominator by multiplying both sides by 2. Once you have all the fractions gone, you'll have a quadratic equation. When you have a quadratic equation, you move everything to one side of the equation and set it = 0. Then factor and solve for x. Of course you need to know how to factor, but just see if you can get rid of the fractions and then get everything to one side of the equation. If that makes sense : )

Answer 3

@Sav_1012 has been posting questions and they are test questions @Psymon
+ SHE DOES NOT TRY.

Answer 4

http://openstudy.com/study#/updates/52224efee4b06211a67f1593

Answer 5

gtfo of here.

Answer 6

i never said i wasnt willing. seriously get the fu ck off my questions.

Answer 7

I was clearly explaining but you did not even try.

Answer 8

http://openstudy.com/users/sav_1012#/updates/522247fde4b06211a67f1354

Answer 9

get off.

Answer 10

Nahh I'm good, thanks.

Answer 11

lol k

Answer 12

:)

Answer 13

:))