Suppose 80 points are placed around a circle. A line segment is drawn between each pair of points.How many line segments are drawn?
you have 80 points along a circle and you have to choose 2 of them to make a line segment the number of ways to do this is \(\binom{80}{2}\) some times written as \(_{80}C_2\) and read "80 choose 2"
you know how to compute that number?
I have not idea
i take it this is some combinatorics class or maybe probability?
it is my MGF1107 class LIberal Art II
liberal arts?! lol have fun actually it is the same idea as your previous problem
\[\binom{80}{2}=\frac{80\times 79}{2}\]
yeah I am completely lost
would the answer be 3160
yeah i can see what you need to know is a formula for \(\binom{n}{k}\) the number of ways you can choose \(k\) items from a set of \(n\)
ok
the formula is \[\binom{n}{k}=\frac{n!}{k!(n-k)!}\] but you don't really use it exactly in this form have you seen this before?
no
oh then i don't know how you are expected to do the problem without it what methods are you supposed to use?
you certainly don't have time to count them all!
I am not sure because this math class is online
you got a book?
yeah online and I am lost in the book
I dont see the formula in the book at all
hmm you need it for the last problem you asked as well, the maze problem
maybe it is written as \(_nC_k\)
is there anything there about pascal's triangle?
I know i posted the maze i dont know if you can click on the link i posted
let me see if i can find it, i can help you with that one as well
thank you I sent you the link to my book
yeah i got it what page are you on?
problem solving
do you know what page it is?
page 13
page 14
jeez you are right, i guess you are just supposed to "figure it out"
let me find your last problem and see if i can help you with it
ok thank you
I am so lost thank you for helping
could you repost? i can't find the damned problem
yeah
you can put it here if you like
Morris Mouse can easily find his way through the maze from the entrance A to the exit B. However, he only receives food if he finds the exit without going west or south. (North is towards the top of the page.) How many different paths can he take through the maze to receive food? (Note: Different paths have at least one distinct section. See the diagram for an example.) https://angel.spcollege.edu/AngelUploads/QuestionData/2bfb73e4-236a-4599-bf10-af270b97f4c8/61324442322642544448.png# {7a7875da-913f-49bb-a105-e7c68ffc0aca}
ok
ok now before we do this one lets redo the first one with a method that might be more suitable
ok
pick one of the 80 points it has 79 places to go pick the next one it has 78 place to go (because you don't want to count the first one twice) pick the next one it has 77 places to go etc
so you can solve this by adding \[79+78+77+76+...+2+1\] or \[1+2+3+...+77+78+79\] now i do notice that you have a formula for this in the book
ok
the formula is \[1+2+3+...+n=\frac{n(n+1)}{2}\] which in your case is \[\frac{79\times 80}{2}\] same exact answer as before
3160 was the answer
yes
now for the next one, i cannot think of simple explanation but i can explain it
i have 10 questions to do. Can you help me with them
Thank you. Your such a big help
lol sure until i get tired
lol ok thank you. I need to pass this class for my RN degree
in the maze problem you have, you can think of it this way: you have to go to the right 5 times and up 5 times, in some order
ok I am looking at it now
let me know when it is clear that you are going to take 5 steps right and 5 steps up to get from point A to point B
ok so I took 5 steps to the right and 5 up
that would give me 25 steps
now the question is, how many ways can you do that here is one way \[(r, r, u, r, u, u, r, u, r, u)\]
ok
if i replace all \(r\) by \(0\) and all \(u\) by \(1\) we turn \[(r, r, u, r, u, u, r, u, r, u)\] in to \[(0,0,1,0,1,1,0,1,0,1)\]
now I am lost
forget that then, it is unnecessary
sorry
the question is, how many ways can i fill ten slots with 5 \(r\) and 5 \(u\)
oh ok
now we have to use the formula i wrote above i see no way around it
ok let me right that formula down
the question translates in to this "how many ways can i pick 5 out of the 10 slots to put an \(r\)?"
and the answer is \[\binom{10}{5}=\frac{10\times 9\times 8\times 7\times 6}{5\times 4\times 3\times 2}\]
as i said this i called "10 choose 5" and we can ask wolfram for the answer, although this is very easy to compute if you cancel first and multiply last
ok let me solve this
ok
252 is the answer
yes
thank you!!
yw next?
What is the 76th decimal digit in the decimal representation of
13/11
that can't be that hard, you only have two to choose from
What is the 76th decimal digit in the decimal representation of 13/11 https://angel.spcollege.edu/AngelUploads/QuestionData/acae6292-47fd-4c42-9c1a-f19417bc9091/62K31R313554314L4653.png# {2752460f-f064-4665-9c63-2331704bfd48}
76 is an even number right?
so it is 8
lots easier than the last two by far
yes that is what i got
lol
ok i hope the rest are that easy
If two ladders are placed end to end, their combined height is 46.5 feet.One ladder is 3.5 feet shorter than the other ladder.What are the heights of the two ladders?
we are on number 5
you got lots of way to do this you can write an equation if you like or just guess and check
ok what way would be the easy
i am always accused of doing this the not math way but if it was me i would guess if one is 20 and the other is 3.5 longer then it would be 23.5 but then the total would only be \(20+23.5=43.5\) so that is not the right answer try a bigger one
ok
if you want an equation, call one length \(x\) so the other would be \(x+3.5\) and then solve \[x+x+3.5=46.5\]
or as we say in math, \[2x+3.5=46.5\]
can you solve that one? takes two steps subtract \(3.5\) from both sides, divide both sides by \(2\)
ok 21.5
answer would be 21.5 feet and 18 feet
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