in a certain year, the amount A of garbage in pounds produced afte t days by an average household is given by A=6.5t. How many days did it take for the average household to produce 150 pounds of garbarge?
"How many days did it take for the average household to produce 150 pounds of garbarge?"\[ A = 150 \]We can substitute this into the equation already provided: \[ A=150 = 6.5t \]Now we just need to solve for \(t\)\[ 150 = 6.5t \]
\[6.5t \]This is actually multiplication: \[ 6.5\times t \]The inverse is division \[ (6.5\times t)\div 6.5 = t \]If we do this to both sides of the equation simultaneously: \[ 150\div 6.5 = (6.5\times t)\div 6.5 \\ 150\div 6.5 = t \]
23 days
After 23 days, the average household will have produced just under 150 pounds of garbage. On the 24th day they have produced over 150 pounds.
The real question is, do you think you could solve a similar problem on your own from now on?
yeah now i just have to graph it
how would you graph it if i am off a smudge it will be wrong
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