Can you separate the equation below (y^2+2xy)y' + y^2 = 7x into the form of exact equation: M(x,y) dx + N(x,y) dy = 0 ? It seem like impossible ?

Question

Can you separate the equation below (y^2+2xy)y' + y^2 = 7x  into the form of exact equation: M(x,y) dx + N(x,y) dy = 0 ? It seem like impossible ?

anonymous · Answer

as you should know: y'=dy/dx, so
(y^2+2xy)(dy/dx)= 7x- y^2
then:

(y^2+2xy)dy= (7x- y^2)dx

anonymous · Answer

Sorry, how did you get 7x ?

anonymous · Answer

but.... are we supposed to move the x to the right and y to the left?

anonymous · Answer

i mean there is still variable y in the dy equation.

anonymous · Answer

no: the finale shude be:
(y^2+2xy)dy- (7x- y^2)dx =0

anonymous · Answer

ok... my bad....

anonymous · Answer

that's not important. You what exact equation is?

anonymous · Answer

I was confused with the separable equation.. hahaha

anonymous · Answer

ok, :)

anonymous · Answer

thanks a lot....

anonymous · Answer

yw

anonymous · Answer

I cannot give two best answer

anonymous · Answer

Thanks myko

goformit100 · Answer

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