simplify the expression: ((2/b)-(1/3))/((4/b^2)-(1/9))

Question

goformit100 · Answer

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anonymous · Answer

$$\frac{ 2 }{ b }-\frac{ 1 }{ 3 }\div \frac{ 4 }{ b ^{2} }-\frac{ 1 }{ 9 }$$

anonymous · Answer

so lets first look at the first one 
$$\frac{ 2 }{ b}-\frac{ 1 }{ 3 }$$
what is the common denominator

anonymous · Answer

would I have to multiply b to 1/3 and 3 to the 2/b?

anonymous · Answer

yes :)

anonymous · Answer

now what about the second one

anonymous · Answer

so the first one we have 
$$\frac{ b }{ 3b }-\frac{ 6 }{ 3b}$$
right ?

anonymous · Answer

right, and then the second one would be 36/9b^2 and b^2/9b^2

anonymous · Answer

right so we have 
$$\frac{ b -6}{ 3b}\div \frac{ 36-b ^{2} }{ b ^{2} }$$
so what do u do now with dividing fractions

anonymous · Answer

multiply by the recipricol to make it easier?

goformit100 · Answer

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