solve -1 = -2v + 2/3 for v.
was thtat worded like that in the problem
yahh
on your sheet or computer
i mean no
can you copy and paste it??or rite it how the problem was ??
mmkay
Is this it? Solve for v \(-1 = -2v + \dfrac{2}{3} \)
yeah @mathstudent55
-2/3 then correct @mathstudent55
First, subtract 2/3 from both sides. Then, divide both sides by -2. gtg. try it, i'll be back in 20 min.
ugh can i have the answer lol? @dirtydan667
thts against the policy of openstudy i could get banned
and i dont want tht
really? oh its soo hard though
ill show youtep by step with the awnser just one sec
ok thanks
for some stupid reason i cant get it
can you figure the answer out? like explain it to me with the answer in it lol
\(-1 = -2v + \dfrac{2}{3} \) We want v by itself, so first, subtract 2/3 from both sides. \(-1 - \dfrac{2}{3} = -2v + \dfrac{2}{3} - \dfrac{2}{3}\) \(-\dfrac{3}{3} - \dfrac{2}{3} = -2v + \dfrac{2}{3} - \dfrac{2}{3}\) Do the subtractions on both sides. What do you get?
i dont know help please! :(
oh 1/3 = -2v right? @mathstudent55
\(-\dfrac{3}{3} - \dfrac{2}{3} = -2v + \dfrac{2}{3} - \dfrac{2}{3} \) This is the next step. \( -\dfrac{5}{3} = -2v \) \(-2v = -\dfrac{5}{3} \) Now you need to divide both sides by -2, which is the same as multiplying both sides by -1/2.
i got 5 thats not right help! @mathstudent55
\( -2v = -\dfrac{5}{3} \) \( -\dfrac{1}{2} \times ( \dfrac{-2v}{1}) = -\dfrac{1}{2} \times ( -\dfrac{5}{3} ) \) \( v = \dfrac{5}{6} \)
THANKS
You're welcome.
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