Question

Hi can you integrate (-2x^2-x) / (2x^3+x^2+1) with respect to x?

Answer 1

you may need to decompose using the partial fractions technique

Answer 2

ohh i thought u are going to show it up.

Answer 3

but thanks for the tips...

Answer 4

Hai UnkleRhaukus? Are you writing an answer?

Answer 5

I will give the best answer to him. If not..

Answer 6

can you do some thing tricky and make the integrand du/u ?

Answer 7

hmm , it dosen't quite work

Answer 8

is it possible to integrate ?

Answer 9

6x^2+2x doesn't quite make it nice and simple

Answer 10

-x(2x+1) look to see if 2x+1 is a factor of the bottom

Answer 11

i dont think it is.. right?

Answer 12

you can check if you'd like

Answer 13

ok. checking.

Answer 14

nope... it's not

Answer 15

nope...

Answer 16

-1 is a root

Answer 17

Other than partial fraction. is there any shorcut to do this integration ?

Answer 18

i mean any other method. don't care if it's hard.

Answer 19

not that i can think of right now

Answer 20

is it a definite or indefinite integral?

Answer 21

indefinite.

Answer 22

if it is finite, i can just use calculator ;P

Answer 23

hmmm...

Answer 24

see what you get after factoring out the root at -1. partial fraction decomp may be all you have. it's not that bad to use. have you learned it already?

Answer 25

i think doing factoring with that imaginary root will make this problem more complex.

Answer 26

i think, it's better i skip this question.

Answer 27

no... you leave that as a quadratic if you get a complex root

Answer 28

but, partial fractions is fun

Answer 29

it really is kind of cool, but takes a little bit of work

Answer 30

it's ok. i think i will leave this question.. by the way 2 of you are helping me.. but i have to give pgpilot326 as he's trying hard to help me.

Answer 31

thx for that... i'll see what i come up with on the decomp

Answer 32

thanks

Answer 33

\[\frac{ -2x ^{2}-x }{ 2x ^{3}+x ^{2}+1 }=\frac{ -\frac{ 1 }{ 4 } }{ x+1 }+\frac{ -\frac{ 3 }{ 2 } x+\frac{ 1 }{ 4 }}{ 2x^2 - x+1 }\]