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factor (3x-5)(x^2-5) ≤ 0
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Well, both of those are considered prime polynomials, but you can always write a difference like: \(\Large x^2-a\) as a difference of squares: \(\Large (x-\sqrt{a})(x+\sqrt{a})\) in order to have a product of all 1st-degree binomial factors.
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