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Consider the reaction 2NH3(g) yields N2(g) + 3H2(g) If the rate of delta[H2]/delta t is 0.030 mol L-1 s-1, then delta[NH3]/delta t is? Could someone please explain how to do this problem.
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All you need to do is take the stoichiometric coefficients into account, write a ratio and solve algebraically. \(\dfrac{1}{3}\dfrac{d[H_2]}{dt}=\dfrac{1}{2}\dfrac{d[NH_3]}{dt}\)
ok cool. I just wanted to make sure I was going in the right direction.
good stuff
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