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Mathematics 8 Online
OpenStudy (anonymous):

Find the standard form of the equation of the parabola with a focus at (0, 6) and a directrix at y = -6. PLEASE HELP ME

OpenStudy (anonymous):

take any point (x,y) and then use the definition of parabola.

OpenStudy (anonymous):

what @surjithayer

OpenStudy (anonymous):

Let P (x,y) be any point on the parabola. by definition PM=PF

OpenStudy (jdoe0001):

keep in mind that the directrix in a parabola, is equally distant from the vertex as the focus, if the focus is at (0, 6) and the directrix is at y=-6 [ a flat horizontal line down below ], the vertex is half-way between them also recall that a parabola "focus form" equation for a vertical opening parabola is \(\bf (x-h)^2=4p(y-k)\) (h, k) = coordinates of the vertex p = distance from the vertex to the focus/directrix

OpenStudy (anonymous):

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