Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (firejay5):

I am having trouble with my Geometry Homework. We haven't gone over it in class, so we have to learn it by ourselves. I have finished some of it, but not for sure if it's accurate or correct. Medal will be rewarded if answer is correct and accurate and you helped me some. Attachments will be in comment box below

OpenStudy (firejay5):

OpenStudy (mathstudent55):

The first one is correct.

OpenStudy (firejay5):

positive with the reasons

OpenStudy (mathstudent55):

Wait. The first one is an example in your book?

OpenStudy (firejay5):

Yea, I took it, so you knew what we had to do

OpenStudy (mathstudent55):

I see. I see that it's called Example 1.

OpenStudy (firejay5):

Yea

OpenStudy (mathstudent55):

Ok. Now I am at Try These a. 1. Given is correct.

OpenStudy (firejay5):

what about the other 6

OpenStudy (mathstudent55):

2. What is the 10 doing on both sides of the equation? What operation is the 10 involved with?

OpenStudy (firejay5):

multiplying the 2 and the 5

OpenStudy (mathstudent55):

If it's multiplying both sides, what property is it?

OpenStudy (firejay5):

multiplication property

OpenStudy (mathstudent55):

It's not multiplying the 2 and the 5. It's multiplying the fraction of the left side and the fraction on the right side. Yes, "Multiplication property of equality" is the reason for 2.

OpenStudy (firejay5):

#3 is Division Property of Equality

OpenStudy (mathstudent55):

For 3. You are simply dividing the 10 by 2 on the left and the 10 by 5 on the right. This is not a property. It's simply reducing each fraction.

OpenStudy (mathstudent55):

Step 4. The distributive property is applied on each side, so 4. is Distributive property.

OpenStudy (firejay5):

5. Subtraction property of equality 6. Division Property 7. Reflexive Property

OpenStudy (mathstudent55):

In step 5 you go from 5x - 15 = 12 + 2x to 3x - 15 = 12 The 2x was subtracted from both sides, so 5. Subtraction property of equality.

OpenStudy (mathstudent55):

For 6. You go from 3x - 15 = 12 to 3x = 27 15 was added to both sides to get 3x = 27, so 6. is Addition property of addition.

OpenStudy (mathstudent55):

Finally, in step 7. you go from 3x = 27 to x = 9 by dividing both sides by 3, so 7. Division property of equality

OpenStudy (firejay5):

okay thank you and I don't get the 3rd link

OpenStudy (mathstudent55):

In the third link, you need to solve the equation to find out what you are trying to prove.

OpenStudy (firejay5):

like how

OpenStudy (mathstudent55):

Then you can go back to the solution, and justify every step with a reason, and fill in the Prove statement at the top.

OpenStudy (mathstudent55):

We'll solve the equation together first.

OpenStudy (mathstudent55):

We can solve the equation with each step accompanied by a reason. This way the proof part will be done. Then we find out what the solution to the equation is, ans we'll fill out the Prove part of the proof on top. Statements Reasons 1. \(4x + 9 = 18 = \dfrac{1}{2}x \) 1. Given

OpenStudy (firejay5):

Wait am I doing the same thing like the previous page

OpenStudy (mathstudent55):

We can solve the equation with each step accompanied by a reason. This way the proof part will be done. Then we find out what the solution to the equation is, ans we'll fill out the Prove part of the proof on top. Statements Reasons 1. \(4x + 9 = 18 = \dfrac{1}{2}x \) 1. Given

OpenStudy (firejay5):

so basically do the same thing we did before correct

OpenStudy (mathstudent55):

Yes.

OpenStudy (firejay5):

that's what it's asking us to do

OpenStudy (mathstudent55):

Yes, you need a two column proof.

OpenStudy (firejay5):

it did the first statement for us

OpenStudy (mathstudent55):

Here are the first statement and reason again. I had an extra equal sign above by mistake. Statements Reasons 1. \(4x+9=18 - \dfrac{1}{ 2} x\) 1. Given

OpenStudy (mathstudent55):

Now we need to add \( \dfrac{1}{2}x \) to both sides. 2. \(\dfrac{9}{2}x + 9 = 18 \) 2. Addition property of equality

OpenStudy (mathstudent55):

Now we subtract 9 from both sides. 3. \( \dfrac{9}{2}x = 9 \) 3. Subtraction property of equality

OpenStudy (firejay5):

Could you leave it as 4.5

OpenStudy (mathstudent55):

Now we multiply both sodes by 2/9 4. \( x = 2 \) 4. Multiplication property of equality

OpenStudy (firejay5):

Wait

OpenStudy (firejay5):

4. Division Property of Equality, because I divided 9 by 4.5 to get 2

OpenStudy (mathstudent55):

Now that we know the solution is x = 2, we can fill out the line above of what to prove: Prove: x = 2

OpenStudy (mathstudent55):

Yes. If you used 4.5x = 9, then you divide both sides by 4.5 to get x = 2, so for you, Division property is correct.

OpenStudy (firejay5):

so we worked both differently for the last one

OpenStudy (mathstudent55):

That's fine. We are both correct.

OpenStudy (firejay5):

Example 2: Was I correct?

OpenStudy (mathstudent55):

Which link is that?

OpenStudy (firejay5):

4th link

OpenStudy (mathstudent55):

Ok, I'll look.

OpenStudy (firejay5):

My homework goes in order of the links except the first link

OpenStudy (mathstudent55):

For the 4th lionk: All your answers are correct exept for the last one.

OpenStudy (firejay5):

what's c

OpenStudy (mathstudent55):

x + 7 = 10 What do you do to x + 7 to end up with x?

OpenStudy (firejay5):

subtraction

OpenStudy (mathstudent55):

Right, so the answer is: Subtraction property of equality?

OpenStudy (firejay5):

But it asked for: State the property of equality that justifies the conclusion of the statement

OpenStudy (mathstudent55):

That is it.

OpenStudy (firejay5):

I took it like substituting 3 for x

OpenStudy (firejay5):

Was I wrong

OpenStudy (mathstudent55):

That is not substitution. This is substitution: Given: x = 2 y + x = 10 Prove: y = 8 1. x = 2 1. Given 2. y + x = 10 2. Given 3. y + 2 = 10 3. Substitution 4. y = 8 4. Subtraction property of equality. What happened from step 2 to step 3? Notice that in step 3, x was substituted by what x is equal to, 2. That is what substitution is.

OpenStudy (mathstudent55):

Yes, you were wrong because there was no substitution done in your problem in Link #4.

OpenStudy (firejay5):

Is link 5 right? and I need a little help with link 6

OpenStudy (mathstudent55):

Substitution is a property of equality. It's just not the one that used in that probelm.

OpenStudy (firejay5):

Is link 5 right, and I need help with link 6

OpenStudy (mathstudent55):

5a and 5b are correct. In 5c, you switched the hypothesis and the conclusion.

OpenStudy (firejay5):

so switch x^2 = 16 and x = 4

OpenStudy (mathstudent55):

Yes. In link 6, the hypothesis and conclusion are easy to do like you did in link 4.

OpenStudy (mathstudent55):

a, The part after "if" is the hypothesis. b. The part after "then" is the conclusion. c. Think of any two odd numbers and add them together. Is the sum odd or even?

OpenStudy (firejay5):

A. 2 #'s are odd B. sum is odd C. 25 + 99 = 124, so two numbers that are odd, the sum should be even

OpenStudy (firejay5):

is my answer correct

OpenStudy (mathstudent55):

For a and b you are correct. For c you are on the right track. You need to show one example where the conclusioin is false. You did it by choosing 25 and 99 and showing the sum is 124, an even number. Therfeore, you have shown a counterexample. All you need to do is state, "odd numbers 25 and 99 have a sum of 124, an even number, proving the if-then statement flase."

OpenStudy (firejay5):

Thank you for your help @mathstudent55

OpenStudy (mathstudent55):

You're welcome.

OpenStudy (firejay5):

@mathstudent55 Somethings you were wrong though

OpenStudy (firejay5):

You were wrong on 4th link on C, it was substitution property

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!