so if I have an equation with two fractions in it and two whole numbers and one of the fractions has an x next to it in order for me to get rid of those fractions I multiply by the LCD but do I also multiply the whole numbers by that?

Question

jim_thompson5910 · Answer

what is the equation

anonymous · Answer

well like the one we just did. what if there was a whole number in there would I have to also times that by the LCD?

jim_thompson5910 · Answer

yes you need to multiply every term by the LCD so things balance out

jim_thompson5910 · Answer

but what is the equation?

anonymous · Answer

2x+3=3/4x--2

phi · Answer

$$ 2x+3=\frac{3}{4}x -  -2 $$
I would immediately write -(-2) as +2 to avoid mistakes
$$ 2x+3=\frac{3}{4}x +2 $$
to get rid of the 4, multiply both sides of the equation (and *all* terms) by 4.  like this
$$ 4\cdot 2x+ 4\cdot 3= 4\cdot \frac{3}{4}x + 4\cdot 2 $$
now simplify

phi · Answer

the first term is 4*2*x   which is 8*x , usually written 8x

4*3 is 12
$$ 4 \cdot \frac{3}{4} \cdot x = \frac{4\cdot 3\cdot x}{4} \text{ or } \frac{4}{4}\cdot \frac{3x}{1}= 3x$$

phi · Answer

the last term 4*2  is 8

you get
8x +12 = 3x +8