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evaluate the difference quotient for the given function f(x)= 1/x, f(x)-f(a)/x-a
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\[f(x)= 1/x\]\[f(a) = 1/2\] \[\frac{f(x)-f(a)}{x-a} =\frac{\frac 1x -\frac 1a}{x-a} \]
You have to simplify it more.
What do I do next?
First simplify the numerator: \[ \frac 1 x - \frac 1 a = ? \]
\[ \frac 1x - \frac 1a = \frac a{xa}-\frac x{xa} = \frac{a-x}{xa} \]
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So we have \[\large \frac{\frac{a-x}{xa}}{x-a} = \frac{a-x}{(xa)(x-a)} \]
and so the x-a and a-x cancels out?
Yeah, they cancel out to \(-1\).
Assuming that \(x\neq a\)
thank you!
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