What is the limit as x approaches -3 of the function 3-lxl/ 3+x

Question

anonymous · Answer

Graph it and see what happens.

anonymous · Answer

im not allowed to use a graph on this one

anonymous · Answer

What are you allowed to use?

anonymous · Answer

anonymous · Answer

I'm allowed to do it algebraically only lol @wio

anonymous · Answer

Okay, if you want to do it algebraically, then you have to split the function up into two cases:  When $x$ is negative and when it is positive.

anonymous · Answer

oh i got it i as looking at positive 3 thank you anyway

anonymous · Answer

$$
f(x) =\begin{cases}
\frac{3-x}{3+x} &x>0\
\frac{3+x}{3+x}  &x<0
\end{cases}
$$We want to use that $x<0$ case.

anonymous · Answer

$$
\lim_{x\to -3}\frac{3-|x|}{3+x} = \lim_{x\to -3}\frac{3+x}{3+x} = \lim_{x\to -3}1 = 1
$$

anonymous · Answer

No medal?