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Discrete Math
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Use the method of Mathematical Induction to prove that, for every natural number n, the number n^2 + 5n + 6 is even.
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first of all we will check for P(1) is it true or not?? for dat we will put n=1.luckily dat is true.....1+5+6 is divisible by 2 Now we will assume dat for P(K) this equation is true.......nd the equation is K^2+5K+ 6 ----------equation no.1 Now we are going to try to prove dat dis equation is true for P(K+1) for dat (K+1)^2+5(K+1)+6 K^2+2k+1+5K+5+6 K^2+5K+6 + 2K+6 Now as we know dat K^2+5K+6 is divisible by 2 nd 2(k+3) is also divisible by Therefore P(K+1) is satisfied Hence Proved Hope u get What m tryin to say
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