Question

factor
27^6s+64y^3t
24x^2a-6

Answer 1

I'm not sure what your question is. Can you use the equation editor to clear it up?

Answer 2

\[27x ^{6s}+64y ^{3t}\]

Answer 3

There is no variable that can be factored out so look at the coefficients and see if they have a common factor.

Answer 4

\[24x ^{2a}-6\]

Answer 5

In the expression \(27x ^{6s}+64y ^{3t}\) the coefficients are perfect cubes. You can figure that out by prime factorization.

Answer 6

so i dont know how to do that

Answer 7

I'm not sure what the question is asking for. Is this on a computer program?

Answer 8

its asking to factor

Answer 9

I'm sorry, maybe someone else can help you.

Answer 10

The first expression looks like it could be the sum of two cubes.

[3^(2s)]^3 + [4y^t]^3

Then it could be broken down further,

according to

a^3 + b^3=(a+b)(a^2 - 2ab + b^2)

Answer 11

ok but what would i do with the s and t

Answer 12

@Julian101 wouldn't that mean the s exponent needs to be raised to the third power?

Answer 13

Nevermind, it doesn't.

Answer 14

When an exponent is raised to a power, you multiply the exponents.

Answer 15

but dont you do that when x and y are the same

Answer 16

its asking to factor

Answer 17

I'm thinking that "a" would be 3^(2s) and "b" would be 4y^t.

So (3^(2s) + 4y^t) (9^(4s) - 2(3^(2s))(4y^t) + 16y^(2t))

Answer 18

could u write that withe the
equation thingie

Answer 19

I can't seem to get the equation writer to work on my end. It hasn't worked for me in several days, and what the others have written isn't showing up in the equation symbols either, so it's very hard to read.

Answer 20

\((3x^{2s} + 4y^t) (9x^{4s} - 2(3^{2s})(4y^t) + 16y^{2t})\)
I think this is Julian's expression.

Answer 21

then would that be like the final answer

Answer 22

I added an x after the 3 and 9, I should have added an x after the 3 in the middle term as well.

Answer 23

\((3x^{2s} + 4y^t) (9x^{4s} - 2(3x^{2s})(4y^t) + 16y^{2t})\)

Answer 24

As to that being the final answer, I don't know. Maybe those middle terms need to be multiplied.

Answer 25

I think I made a mistake, the 2 should be removed from the middle of the second expression in brackets.

Answer 26

no there is something wrong.
\[a ^{3}+b ^{3}=\left( a+b \right)\left( a ^{2}-ab+b ^{2} \right)\]

Answer 27

a^3 +b^3 = (a+b) (a^2 -ab +b^2) i.e., there is NOT a 2 in front of the ab

Answer 28

Sorry about that. Other than that, I think that should be final, as I don't think it can be reduced further.

Answer 29

For the second question, factor out 6, so now you have

6(4x^2a -1) then break down the expression in brackets

= 6(2x^a - 1)(2x^a + 1)