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Mathematics 17 Online
OpenStudy (anonymous):

MATH HELP ! Medals will be given !

OpenStudy (anonymous):

Pierre deposited 9,875 into a savings account 23 years ago. The account has a interest rate of 2.7% and the balance is currently 18,374.86. How often does the interest compound?

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

@pathosdebater

OpenStudy (anonymous):

wow ok i bet we can do this

OpenStudy (anonymous):

\[18,374.86.= 9,875(1+\frac{.027}{n})^{23n}\] and some how we need to solve for \(n\)

OpenStudy (anonymous):

After this question can you check my answers on my other questions please

OpenStudy (anonymous):

What do we do to solve for n

OpenStudy (anonymous):

divide by \(9875\) first

OpenStudy (anonymous):

actually, the first thing i would do would be guess lets guess monthly and see if it is right

OpenStudy (anonymous):

Ok so divide what to what ?

OpenStudy (anonymous):

hmm very close

OpenStudy (anonymous):

I'm still lost

OpenStudy (anonymous):

@satellite73 I was about to solve it but then again, there is a "n" inside the brackets which makes simplifying a little harder than I thought. You COULD use newton's method on it which is a repetitive formula for finding the zeroes of any function using derivatives from calculus...I'm just thinking if there is a algebraically simpler way...

OpenStudy (anonymous):

...hmm

OpenStudy (anonymous):

start here \[18,374.86= 9,875(1+\frac{.027}{n})^{23n}\] and then divide both sides by \(9875\) to get \[\frac{18374.86}{9875}=(1+\frac{.027}{n})^{23n}\]

OpenStudy (anonymous):

oh damn, the method i was trying will not work i think it is better to guess and check

OpenStudy (anonymous):

Yeah but then even with using logarithms...it is still pretty complex

OpenStudy (anonymous):

is it annually

OpenStudy (anonymous):

really?!

OpenStudy (anonymous):

huh ?

OpenStudy (anonymous):

no actually it is not annually because \[9875(1.027)^{23}=18224.57\]

OpenStudy (anonymous):

its quarterly

OpenStudy (anonymous):

ok lets try that

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

\[9875(1+\frac{.07}{4})^{4\times 23}=18336.98\] http://www.wolframalpha.com/input/?i=9875%281%2B.027%2F4%29^%284*23%29

OpenStudy (anonymous):

i made a typo there, but the wolfram answer is correct

OpenStudy (anonymous):

so was i right ?

OpenStudy (anonymous):

no that is too small by a little

OpenStudy (anonymous):

here is monthly http://www.wolframalpha.com/input/?i=9%2C875%281%2B.027%2F12%29^%2812*23%29

OpenStudy (anonymous):

danngit. i can't be daily

OpenStudy (anonymous):

we can try daily

OpenStudy (anonymous):

looks like we have a winner!

OpenStudy (anonymous):

Hmmmm, DAILY :)

OpenStudy (anonymous):

go with daily

OpenStudy (anonymous):

nothing like a little guess and check

OpenStudy (anonymous):

is it daily 100%

OpenStudy (anonymous):

According to wolfram alpha, \[n\phantom{.}\dot{=}\phantom{.}0.00746783522465871\]

OpenStudy (anonymous):

so what do you think it is @KeithAfasCalcLover daily ?

OpenStudy (anonymous):

it is daily because we checked it

OpenStudy (anonymous):

Well im not sure, ahah I was just solving the equation was given.

OpenStudy (anonymous):

I have to be honest, I never liked financial applications. I tried to focus on the equation solving part.

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