f(x)= {2x-3, x cannot equal 2 and 0, x=2} has a removable discontinuity. Redefine f(x) so that it is continuous at x=2.

Question

anonymous · Answer

replace $x$ by $2$ and see what you get

anonymous · Answer

or better yet, just remove all the verbiage and write 
$$f(x)=2x-3$$

anonymous · Answer

I got 1?

anonymous · Answer

yeah ignore my first answer, just make $f(x)=2x-3$ for all $x$
then it is continuous for sure
it is a line

anonymous · Answer

what about the 0?

anonymous · Answer

what about it?

anonymous · Answer

its the answer just f(x)=2x−3 ?

anonymous · Answer

$$f(x)  = \left\{\begin{array}{rcc}
2x-3 & \text{if}  & x \neq  2 \
0& \text{if}  & x =2
\end{array}
\right.
$$

anonymous · Answer

the only reason this is not continuous at $2$ is because $2\times 2-3=-1$ and this function is defined so that $f(2)=0$ rather than $-1$ for some reason
to get rid of that stupid discontinuity, make the function just $f(x)=2x-3$ for all $x$ like normal, and then it is  continuous

anonymous · Answer

oh okay thank you so much:)

anonymous · Answer

can i ask you another question