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Mathematics 26 Online
OpenStudy (anonymous):

Solve a through j. a=? b=? c=? d=? e=? f=? g=? h=? i=? j=?

OpenStudy (anonymous):

OpenStudy (akashdeepdeb):

Use the 30-60-90 triangle ratios And the ratios of the other special triangles. :)

OpenStudy (anonymous):

does b= 4(square root of 2) and does a= 4?

OpenStudy (loser66):

yup

OpenStudy (anonymous):

and does c= 5(squareroot of 3) and does d=2?

OpenStudy (loser66):

c=5\(\sqrt2\)

OpenStudy (loser66):

yup, d =2

OpenStudy (anonymous):

thats what i meant srry, e=4 f= 5(square root of 3)

OpenStudy (anonymous):

h= 10(squareroot of 3)

OpenStudy (anonymous):

and g is about 60 degrees

OpenStudy (anonymous):

i= square root of 3/3

OpenStudy (anonymous):

and j=1?

OpenStudy (loser66):

redo e

OpenStudy (loser66):

f is correct

OpenStudy (loser66):

h is correct

OpenStudy (loser66):

g is correct

OpenStudy (anonymous):

hmm is e 4(squreroot of 3)?

OpenStudy (loser66):

redo i

OpenStudy (anonymous):

hypotenuse= 2 X shorter leg. e=2X2 e=4

OpenStudy (loser66):

Oh, I am sorry, e =4. You are correct, then

OpenStudy (anonymous):

hypotenuse= leg X squareroot of 2 squareroot of 6 = i(square root of 2) squareroot of 6/ square root of 2=i squareroot of 1/square root of 3= i 1/squareroot of 3= i 1/square root of 3 X squareroot of 3/squareroot of 3= i squareroot of 3/ 3= i

OpenStudy (loser66):

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