Solve a through j.
a=? b=? c=? d=? e=? f=? g=? h=? i=? j=?
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OpenStudy (anonymous):
OpenStudy (akashdeepdeb):
Use the 30-60-90 triangle ratios
And the ratios of the other special triangles. :)
OpenStudy (anonymous):
does b= 4(square root of 2) and does a= 4?
OpenStudy (loser66):
yup
OpenStudy (anonymous):
and does c= 5(squareroot of 3) and does d=2?
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OpenStudy (loser66):
c=5\(\sqrt2\)
OpenStudy (loser66):
yup, d =2
OpenStudy (anonymous):
thats what i meant srry, e=4 f= 5(square root of 3)
OpenStudy (anonymous):
h= 10(squareroot of 3)
OpenStudy (anonymous):
and g is about 60 degrees
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OpenStudy (anonymous):
i= square root of 3/3
OpenStudy (anonymous):
and j=1?
OpenStudy (loser66):
redo e
OpenStudy (loser66):
f is correct
OpenStudy (loser66):
h is correct
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OpenStudy (loser66):
g is correct
OpenStudy (anonymous):
hmm is e 4(squreroot of 3)?
OpenStudy (loser66):
redo i
OpenStudy (anonymous):
hypotenuse= 2 X shorter leg.
e=2X2
e=4
OpenStudy (loser66):
Oh, I am sorry, e =4. You are correct, then
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OpenStudy (anonymous):
hypotenuse= leg X squareroot of 2
squareroot of 6 = i(square root of 2)
squareroot of 6/ square root of 2=i
squareroot of 1/square root of 3= i
1/squareroot of 3= i
1/square root of 3 X squareroot of 3/squareroot of 3= i
squareroot of 3/ 3= i