Use basic identities to simplify the expression.

sin2θ + tan2θ + cos2θ

Choices are:
sec2θ

cos3θ

sin θ

tan2θ

Question

Use basic identities to simplify the expression.

sin2θ + tan2θ + cos2θ

Choices are:
sec2θ

cos3θ

sin θ

tan2θ

anonymous · Answer

This was all I got so far. I'm not sure what to do next!
1/csc+sin/cos+1/sec

debbieg · Answer

Are you sure you've copied the problem down correctly? Even using a graphing tool, I'm not finding that any of those choices are equivalent to the original expression....?

anonymous · Answer

Yes! Oh wait sorry, all the numbers are supposed to be exponents.
sin^2θ + tan^2θ + cos^2θ

sec^2θ
cos^3θ
sin θ
 tan^2θ

debbieg · Answer

ah-hah, that will make a big difference... ;)

debbieg · Answer

so it's $\sin^2\theta+\tan^2\theta+\cos^2\theta$, right?

anonymous · Answer

yes!

debbieg · Answer

Use your Pythagorean identities... specifically:

 $\sin^2\theta+\cos^2\theta=1$

And also

 $\tan^2\theta+1=\sec^2\theta$

Now that we have the right problem, it should be pretty trivial. :)

anonymous · Answer

Is it tan^2θ? :O