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Mathematics 8 Online
OpenStudy (anonymous):

Determine whether the vectors u and v are parallel, orthogonal, or neither. u = <10, 0>, v = <0, -9>

OpenStudy (anonymous):

no :( LOL i don't know how to tell if they are p,o, or neither

OpenStudy (anonymous):

@Loser66

OpenStudy (anonymous):

uhhh I remember learning a little bit about that a while ago but I really don't know off the top of my head

OpenStudy (anonymous):

it be 0 right?

OpenStudy (anonymous):

@Loser66

OpenStudy (anonymous):

lol I researched the rule :)

OpenStudy (anonymous):

it's parallel?

OpenStudy (anonymous):

The dot product is basically the product of the magnitudes of two vectors times the cosine of the angle between them. If the angle is 90 degrees, cosine is 0, so the dot product is 0. If the angle is 0 degrees, so cosine is 1, so the dot product is the product of the magnitudes of both vectors.

OpenStudy (anonymous):

OH!! nevermind!

OpenStudy (anonymous):

I see on another site if the dot prod. is equal to 0 it's perpendicular.

OpenStudy (anonymous):

I guess in this case it be neither then. @Loser66 @salehhamadeh

OpenStudy (anonymous):

@Loser66 No one learns without exploring. Just as you, I am trying to guide people to the right place. @alibea Another way to find the dot products is by using their components. For example, <u1, v1> dot <u2, v2> = u1*u2 + v1*v2. Use this formula and tell me what you find.

OpenStudy (anonymous):

I got 0 @salehhamadeh

OpenStudy (anonymous):

If you get 0, they are orthogonal. If you get the product of both magnitudes, they are parallel. If you get a number in between, they are niether.

OpenStudy (anonymous):

@alibea Correct. Now you can solve it, but I suggest that you read more abut vector operations. khanacademy.org has a cool set of videos on these topics. This will give you an intuition on where this formula comes from. @Loser66 No problem :)

OpenStudy (anonymous):

ahh okay! thanks so much for your help both of you :) sometimes when I read things on my own especially with math it looks like a bunch a mumbo jumbo haha glad to have you guys. @salehhamadeh @Loser66

OpenStudy (anonymous):

@alibea You're welcome

OpenStudy (anonymous):

@salehhamadeh not to bother you but would you mind helping me with another question?:l

OpenStudy (anonymous):

@alibea What's your question?

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