Question

2/3x +4=2x

Answer 1

WELCOME TO OPENSTUDY!! :D

Answer 2

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Answer 3

To your question:

First bring all terms containing x to one side and constants to other side.

Answer 4

(3/2)(2/3x) + (3/2)(4)= (3/2)(2x)

Answer 5

Delta = (- 3)² - 4 * 2 * (- 4) = 9 + 32 = 41 x1 = (3 - sqr (41)) / 4 x2 = (3 + sqr (41)) / 4 <=> 2x² - 3x - 4 = 2 * (x - ((3 + sqr (41)) / 4)) * (x - (3 - sqr (41)) / 4)) <=> 2x² - 3x - 4 = 2 * 1/4 * 1/4 * (4x - 3 - sqr (41)) * (4x - 3 + sqr (41)) <=> 2x² - 3x - 4 = 1/8 * (4x - 3 - sqr (41)) * (4x - 3 + sqr (41)) roots are irrational because sqr (41) is irrationa

Answer 6

Is the question that complicated?

Answer 7

no

Answer 8

\[4 = 2x - 2/3x \]
\[4 = 6/3x - 2/3x\]
\[4 = 4/3 x\]
\[4*3 = 4/3x *3\]
\[12 = 4x\]\[12/4 = 4x / 4\]

Answer 9

Final Answer: x = 3

Answer 10

Satellite is here :)

Answer 11

\[\frac{2}{3}x+4=2x\] maybe multiply by 3 and get
\[2x+12=6x\] subtract \(2x\) to get \(12=4x\) divide by \(4\) and get \(3=x\)

Answer 12

alternatively, start with
\[\frac{2}{3}x+4=2x\] subtract \(\frac{2}{3}x\) from both sides and get
\[4=\frac{4}{3}x\] then multiply both sides by \(\frac{3}{4}\) and get
\[4\times \frac{3}{4}=x\] or \(x=3\)