-4x^48 times 1/x^86
i get -4/x^-38
looks goodto me
I thought that as well, but the answer states it as \[-4/x^(38)\]
But if I was right then we could re write it as -4x^38?
This is the real question.... limx→−∞−9x^86−4x^48−2 −2x86+7x46−10
oh i see i was wrong, sorry
Its Ok, I am just a little confused on why it doesnt seem to be adding up
\[\frac{-4x^{48}}{x^{86}}=\frac{-4}{x^{86-48}}=\frac{-4}{x^{36}}\]
ooh i see your question, answer has nothing to do with that at all
both numerator and denominator of your rational function are polynomials of degree 86
Ok, I thought the exponent rules were x^m/x^n = x^(m-n)
since the degrees are the same, the limit as \(x\to \infty\) is the ratio of the leading coefficients
which in your case is \(y=\frac{9}{2}\)
as for the rules of exponents, which i repeat has nothing to do with this question you are right \[\frac{x^m}{x^n}=x^{m-n}\]
Ok I think i am catching on, the rules change since the limit is approaching infinity?
no, the rules of exponents don't change at all
Ok I see the degree of 9 and 2 are to the 86th,
you are not being asked to divide you cannot divide term by term in any case
\[\frac{−9x^{86}−4x^{48}−2}{ −2x^{86}+7x^{46}−10}\] is your rational function
you cannot divide piece by piece you would have to divide using long division, but you are not asked to divide
you are asked for the horizontal asymptote since the degrees are the same, it is the ratio of the leading coefficients
the lower degrees are unimportant as you go to \(\infty\) so this really behaves just like \[\frac{-9x^{86}}{-2x^{86}}=\frac{9}{2}\]
Oh Awesome I see, I just saw exponets and when I tried the rule, it threw me for a loop
Oh Awesome I see, I just saw exponets and when I tried the rule, it threw me for a loop
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