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Mathematics 11 Online
OpenStudy (anonymous):

-4x^48 times 1/x^86

OpenStudy (anonymous):

i get -4/x^-38

OpenStudy (anonymous):

looks goodto me

OpenStudy (anonymous):

I thought that as well, but the answer states it as \[-4/x^(38)\]

OpenStudy (anonymous):

But if I was right then we could re write it as -4x^38?

OpenStudy (anonymous):

This is the real question.... limx→−∞−9x^86−4x^48−2 −2x86+7x46−10

OpenStudy (anonymous):

oh i see i was wrong, sorry

OpenStudy (anonymous):

Its Ok, I am just a little confused on why it doesnt seem to be adding up

OpenStudy (anonymous):

\[\frac{-4x^{48}}{x^{86}}=\frac{-4}{x^{86-48}}=\frac{-4}{x^{36}}\]

OpenStudy (anonymous):

ooh i see your question, answer has nothing to do with that at all

OpenStudy (anonymous):

both numerator and denominator of your rational function are polynomials of degree 86

OpenStudy (anonymous):

Ok, I thought the exponent rules were x^m/x^n = x^(m-n)

OpenStudy (anonymous):

since the degrees are the same, the limit as \(x\to \infty\) is the ratio of the leading coefficients

OpenStudy (anonymous):

which in your case is \(y=\frac{9}{2}\)

OpenStudy (anonymous):

as for the rules of exponents, which i repeat has nothing to do with this question you are right \[\frac{x^m}{x^n}=x^{m-n}\]

OpenStudy (anonymous):

Ok I think i am catching on, the rules change since the limit is approaching infinity?

OpenStudy (anonymous):

no, the rules of exponents don't change at all

OpenStudy (anonymous):

Ok I see the degree of 9 and 2 are to the 86th,

OpenStudy (anonymous):

you are not being asked to divide you cannot divide term by term in any case

OpenStudy (anonymous):

\[\frac{−9x^{86}−4x^{48}−2}{ −2x^{86}+7x^{46}−10}\] is your rational function

OpenStudy (anonymous):

you cannot divide piece by piece you would have to divide using long division, but you are not asked to divide

OpenStudy (anonymous):

you are asked for the horizontal asymptote since the degrees are the same, it is the ratio of the leading coefficients

OpenStudy (anonymous):

the lower degrees are unimportant as you go to \(\infty\) so this really behaves just like \[\frac{-9x^{86}}{-2x^{86}}=\frac{9}{2}\]

OpenStudy (anonymous):

Oh Awesome I see, I just saw exponets and when I tried the rule, it threw me for a loop

OpenStudy (anonymous):

Oh Awesome I see, I just saw exponets and when I tried the rule, it threw me for a loop

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