Use an exponential model to solve the problem: The population of Knoxville is 500,000 and is increasing at the rate of 3.25% each year. Approximately when will the population reach 1 million?
@satellite73 please help
the population starts at 500000, lets just say at t=0 after the first year, t=1 the population is increased by 3.25% so the population would be 500000 + 500000 ( .0325) or 500000(1.0325) lets consider the next year t=2 the population increases another 3.25% from the last year so the population will now be 500000(1.0325)(1.0325) or \[500000(1.0325)^2\]
now considering the 3rd year, t=3 it would be 500000(1.0325)(1.0325)(1.0325) hopefully you see the pattern by now so if we were to write this as an equation for "t" years later it would look like \[P= 500000 (1.0325)^t\] where P is the total population at "t" years later
in the case of your question, you want to determine the number of years it takes for the initial population of 500000 to reach 1 mil in which case, P= 1000000, and solve for t
any questions?
just one... for the equation 1000000=500000(1.0325)^t how do I get the exponent down?
natural log rules specifically power rule \[\ln ( x ^y) = y \ln (x)\]
got it thanks
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