Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary.
B = 74°, a = 14 cm, c = 20 cm
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OpenStudy (akashdeepdeb):
Do you know the law of sines?
OpenStudy (anonymous):
WOOO got it :D I found the answer as 134.58
OpenStudy (akashdeepdeb):
Oh Great! :D
OpenStudy (anonymous):
wait let me check first, I used the formula 1/2acsinB?
OpenStudy (anonymous):
LOL thank you xD but there is one more question I actually need help with about triangles, mind helping me?
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OpenStudy (akashdeepdeb):
Not at all.
OpenStudy (anonymous):
yay thank you!! the question is
Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles.
B = 49°, a = 16, b = 14
OpenStudy (anonymous):
I am really finicky with law of sines D:
OpenStudy (akashdeepdeb):
|dw:1378147440711:dw|
OpenStudy (akashdeepdeb):
Do you know heron's formula?
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OpenStudy (anonymous):
yeah I know that formula!!! I think somewhere in the mix of me finding it I screw up LOL! let me try xD
OpenStudy (akashdeepdeb):
Okay. :D
OpenStudy (anonymous):
would A be 59.6??!
OpenStudy (akashdeepdeb):
Hold on.
OpenStudy (anonymous):
mmk :)
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OpenStudy (akashdeepdeb):
How much is sin inverse of 0.8252523?
OpenStudy (akashdeepdeb):
Yes you are almost correct!! :D
OpenStudy (akashdeepdeb):
I think it is 55.6 :D
OpenStudy (anonymous):
omg woo :DDD
OpenStudy (anonymous):
ok now what lol
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OpenStudy (anonymous):
@AkashdeepDeb I got C as 71.4 would c be 11.1 then?
OpenStudy (akashdeepdeb):
I am not calculateing but If you are calculating then you are right! :D
OpenStudy (anonymous):
LOL I mess up though!! :( crap. lol let me double check
OpenStudy (akashdeepdeb):
Yes and then just use herons formula!
By finding out s the semi-permiter
\[\sqrt{s(s-a)(s-b)(s-c)}\]
OpenStudy (anonymous):
I can't find little c
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