Question

e^x e^(x+1)=1

how do you combine the exponential expressions in a single exponential expression

Answer 1

\[x^a\cdot x^b = x^{a+b}\]

Answer 2

\[
a^n\times a^m = a^{n+m}
\]In this case \(a=e, n=x, m=x+1\).

Answer 3

so e^x*e^x=e^2x

Answer 4

yep

Answer 5

actually wouldnt it be e^x*e^x=e^2x+1

Answer 6

if you wrote it correctly
\[e^x\cdot e^{x+1} = e^{2x+1}\]

Answer 7

thank you

Answer 8

so what's x?

Answer 9

so first I would have to convert it into a logarithmic equation?

Answer 10

what is 1?

Answer 11

\[1=e^0\]