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OpenStudy (anonymous):

what mass of potassium chlorate is required to supply the proper amount of oxygen needed to burn 71.06 grams of methane? (2KClO3->2KCl + 3O2 and CH4 + 2O2 -> CO2 + H2O) I can't solve this help me please

OpenStudy (anonymous):

I know that you should convert 71.06 grams to moles, but the problem is that the two equations are separated.

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