Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

Use properties of logs to simplify the expression

OpenStudy (anonymous):

\[\log_{9}(x-\sqrt{x ^{2}-45})+ \log_{9}(x+\sqrt{x ^{2}-45})\]

OpenStudy (anonymous):

so what I got was \[\log_{9}45 \] but that's not one of my answer choices. what am I doing wrong?

OpenStudy (anonymous):

these are the answer choices: 1. 1 + log9 5 2. log5 9 3. 1 + log5 9 4. log9 5 5. 9 + log9 5

OpenStudy (mathstudent55):

The sum of logs is the log of the product. \( \log_x a + \log_b y = \log_b xy \)

OpenStudy (mathstudent55):

\(\log_{9}(x-\sqrt{x ^{2}-45})+ \log_{9}(x+\sqrt{x ^{2}-45}) \) \( = \log_{9}[(x-\sqrt{x ^{2}-45})(x+\sqrt{x ^{2}-45})] \) Now use "the product of a sum and a difference equals the difference of two squares" pattern to simplify.

OpenStudy (anonymous):

45?

OpenStudy (mathstudent55):

\( = \log_9 45\) You are correct, but you can go furhter because 45 = 9 * 5.

OpenStudy (anonymous):

oh ok. I just need to know how to do the next step.

OpenStudy (mathstudent55):

\( = \log_9 (9 \times 5) \) Use the rule: log of product = sum of logs.

OpenStudy (mathstudent55):

\( = \log_9 9 + \log_9 5 \) \(\log_9 9\) can be simplified since \( \log_b b = 1\)

OpenStudy (anonymous):

so \[1+\log_{9}5 \]

OpenStudy (mathstudent55):

Exactly. Good job!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!