Question

As concrete dries, it shrinks—the higher the water content, the greater the shrinkage. If a concrete beam has a water content of w kg/m3, then it will shrink by a factor
S =( 0.032w − 2.5)/10,000
where S is the fraction of the original beam length that disappears due to shrinkage.

A beam 12.021 m long is cast in concrete that contains 600 kg/m3 water. What is the shrinkage factor S? S = 0.00167

How long will the beam be when dried? (I NEED HELP WITH THIS SECOND QUESTION)

Answer 1

Since S is the fraction that disappears, the amount that disappears is
12.021 m * 0.00167 = 0.020075 m

The beam will be 12.021 m - 0.020075 m = 12.001 m

Answer 2

@mathstudent55 thank you! (:

Answer 3

wlcm