Question

how do you solve A= h/2x (b1+b2) for b1

Answer 1

Is the equation:
\[A=\left.\left.\frac{h}{2x}\right(b_1+b_2\right)\]
?

Answer 2

\[A= \frac{ h }{ 2 }x (b1+b2)\]

Answer 3

Ah cool. K. So you have:
\[\eqalign{
&1.\phantom{space}A=\left(\frac{h}{2}\right)x(b_1+b_2) \\
&2.\phantom{space}\frac{A}{x}=\left(\frac{h}{2}\right)(b_1+b_2) \\
&3.\phantom{space}\frac{2A}{x}=h(b_1+b_2) \\
&4.\phantom{space}\frac{2A}{xh}=b_1+b_2 \\
&5.\phantom{space}\frac{2A}{xh}-b_2=b_1
}\]
So therefore,
\[b_1=\frac{2A}{xh}-b_2\]
Please let me know if there is a step you didn't understand

Answer 4

Numbered them for conveinience

Answer 5

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Answer 6

thanks! i get it now!