Determine a and b so that the vectors < 1,3a+b,2 > and < 2,−1,a+ b > are parallel.
would i set up 3a+b=-1
if they're parallel one should be a scalar multiple of the other. as such the second should be double the first. set up the equations in that way
3a+b=-(1/2) a+b = 4
where did you get the <-1/2> from
the econd vector should be double the first
i was thinking more along the lines of <1,3a+b,2>=S<2,-1,a+b>
let u = <1, 3a+b, 2> and 2u = <2, 6a+2b, 4>, right? v= <2, -1, a+b> and if v = 2u then 6a+2b=-1 => 3a+b = -(1/2) a+b = 4
ok i understand that but arent they looking for a +b individually or it doesnt matter
yes and you have a system of 2 equations in 2 unknowns... solve using whatever method you prefer.
okay thx
you're welcome... does it all make sense now?
yea
cool!
Join our real-time social learning platform and learn together with your friends!