Question

Night engineers are going on an energy assessment in 3 cars that hold 2, 3, and 4 passengers,
respectively. In how many ways is it possible to transport the 9 engineers to the
manufacturing facility, using all cars?

Answer 1

what?

Answer 2

9C3 =

. 9!
------- =
6! 3!

9 x 8 x 7
------------- = 84 <==ANSWER
3 x 2 x 1

I hope that helps!! :-)

Answer 3

okay thats what i thought can you help me with one other problems?

Answer 4

sure if i can figure it out

Answer 5

A construction company employs two sales engineers, John and Meghan. John does the work
of estimating cost for 70% of the jobs bid by the company. Meghan does the work for 30% of
the jobs bid by the company. It is known that the error rate for John is such that 0.02 is the
probability of an error when he does the work, whereas the probability of an error in the work
of Meghan is 0.04. Suppose the bid arrives and a serious error occurs in estimating cost.
Which engineer would you guess did the work? Explain and show work.

Answer 6

if u can that would be great!

Answer 7

why is it \(\binom{9}{3}\) ?

Answer 8

@satellite73 what bro ?

Answer 9

pretty sure that is not right

Answer 10

i guess but i m just trying to help -_-

Answer 11

you have \(9\) people to order in groups of 2, 3, and 4
i am fairly sure that the number of ways to do this is
\[\frac{9!}{2!3!4!}\]

Answer 12

hey no problem, i just don't think "9 choose 3" is the right way to solve it

Answer 13

you have \(9!\) ways to order the people then divide by the number of ways to permute the people in each car

Answer 14

also notice that the "9 choose 3" approach ignores completely the number of people in each car

Answer 15

ooooo i see cause it has to be either 2 groups or 3 or 4... if it was just random groups then it could be 9 chose 3?

Answer 16

i got it too satellite73 is correct my bad -_-

Answer 17

9 choose 3 has really nothing to do with this problem
it is the way to choose 3 things from a set of 9

Answer 18

it all comes from the counting principle