Use trig identites to transform the left side of equation into the right.
(1+cos theta)(1-cos theta)= sin^2theta
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OpenStudy (aravindg):
1+cos theta =2cos^2 theta/2
OpenStudy (anonymous):
multiply on the left, and get
\[1-\cos^2(\theta)\] then it should be easy enough
OpenStudy (aravindg):
1-cos theta=2sin^2 theta/2
OpenStudy (anonymous):
is it clear that
\[1-\cos^2(\theta)=\sin^2(\theta)\]?
OpenStudy (anonymous):
ooohh. yea. I see.
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OpenStudy (anonymous):
kk good
OpenStudy (anonymous):
thank you(:
OpenStudy (anonymous):
yw
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OpenStudy (anonymous):
use identity ---> a^2 - b^2 for lhs
then prove using cos2 + sin2 = 1
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