Question

vectors again

Answer 1

find the unit vector in the given direction,
multiply it wid the required magnitude

Answer 2

\[\frac{ 1 }{ 10 } <0,3,3>\]

Answer 3

nopes

Answer 4

oooops

Answer 5

we're supposed to find a vector wid magnitude: 10 , and in the direction of vector: <0,3,3>

Answer 6

first find the unit vector in the given direction and then multipluy the unit vector by 10
unit vector along the vector <a,b,c> is given by (<a,b,c> ) /sqrt(a^2 +b^2 +c ^2)

Answer 7

to find that, we can simply find the unit vector in the given direction <0, 3, 3>

<0, 3, 3>
----------
3^2+3^2

Answer 8

Find the magnitude of your current vector then multiply it by the number necessary to make the value = to 10.

Answer 9

*sqrt missing

<0, 3, 3>
----------
sqrt(3^2+3^2)

Answer 10

\[\sqrt{(0)^{2}+(3)^{2}+(3)^{2}}*x = 10\]

Answer 11

1/3sqrt(2) <0,3,3>

Answer 12

yes thats the unit vector. which will have magnitude 1

Answer 13

to get magnitude 10, multiply the unit vector wid scalar 10

Answer 14

alright so the unmbers would be \[<0,\frac{ 10 }{ \sqrt(2) }, 10/\sqrt(2)>\]

Answer 15

looks correct !

Answer 16

yep thank you...but i didn't understand why did we multiplied the magnitude by the unit vector

Answer 17

when we multiply the unit vector by a scalar, its magnitude increases by that factor

Answer 18

its simple as that, you can make urself convinced by doing the reverse process :- take the magnitude, and see if u get 10 back... :)

Answer 19

got it ty

Answer 20

np :)