Solve the seperable differential equation for. \frac(dy)(dx) = \frac(1+x)(xy^(6)) ; \ \ x \gt 0 Use the following initial condition: y(1) = 5 .
\[\Large \frac{dy}{dx}=\frac{1+x}{xy^6}, \qquad\qquad x\gt0, \qquad\qquad y(1)=5\]
What part are you stuck on maria? :o Understand the separation portion of it?\[\Large y^6\;dy=\frac{1+x}{x}\;dx\]
No I don't!!! I forgot ittt
\[\Large \frac{dy}{dx}=\frac{1+x}{xy^6}\]So we want all of our `y and dy` on one side of the equation with all of our `x and dx` on the other side :o So we start by multiplying both sides by y^6.\[\Large y^6\frac{dy}{dx}=\frac{1+x}{x}\]Right? +_+
so what do I have to plug in to get y=? because that part makes sense I just don't know how to use that information further
You need to integrate which will get rid of the differentials. Have you done that part yet? :o\[\Large \int\limits y^6\;dy=\int\limits \frac{1+x}{x}\;dx\]
1/7y^7=(ln|x|)+x
\[\Large \frac{1}{7}y^7=\ln|x|+x+C\] Ok good :) Now we can use our initial condition solve for our unknown constant.
\[\Large y(1)=5\]Plugging in gives us,\[\Large \frac{1}{7}5^7=\ln|1|+1+C\]
11160.71=10.320155+c
Nooo, no decimals! :O And what happened on the right side there..? Recall: ln1=0
111.60.71=1+C
11160=C
fine fine fine :) have your sloppy decimals lol that looks good. So now we plug our c back in. and since we're able to, we should probably solve for y.
\[\Large \frac{1}{7}y^7=\ln|x|+x+11160\]
\[\Large y=?\]
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