Question

in the function h= 80-10t² I get the f'(h) part where -10t² derivate gives -5t (n*x^(n-1))
my memories from high school tell me derivating 80 gives 0, but what is the formula? 80=80^1...
or is it here that x = 0....

Answer 1

Your high school memories are correct, the derivative of a constant is zero.If you think this problem in terms of what a derivative signifies, the rate of change of the function, a fixed value can be only expressed through zero since change is absent. Another way to understand it is trying to imagine the slope of the tangent of a horizontal line.

Answer 2

thanks Jake789, I was almost sure it was that, but I needed a confirmation :)

Answer 3

you're welcome