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Mathematics 19 Online
OpenStudy (anonymous):

Help me!!!

OpenStudy (anonymous):

For which value of x should ✔6x be furthered simplified A. 7 B.5 C. 11 D. 3

OpenStudy (anonymous):

The check make is a adrican sign

OpenStudy (anonymous):

Radical

OpenStudy (anonymous):

i'm not sure but wouldn't you plug in all the available numbers you have for x and by multiplying that with 6 you would then see if the new number you have can be simplified

OpenStudy (anonymous):

I tried that but none of the numbers could be simplified they were all whole

OpenStudy (anonymous):

actually try 3..... your answer would be in a radical form... that's what i think

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

think about it like this 6x3=? what princible root can be found in your answer?

OpenStudy (anonymous):

That's 18

OpenStudy (anonymous):

yup now what can you break 18 down to?

OpenStudy (anonymous):

18 squared is 4.2 so is 6 3

OpenStudy (anonymous):

ok think about it like this.... the square root of 9X2 ... which one of those number can you take the square root of?

OpenStudy (anonymous):

2?

OpenStudy (anonymous):

no 9 the sqaure root of 9 is 3 so wouldn't it be |dw:1378222275074:dw|

OpenStudy (anonymous):

Oh yes!

OpenStudy (anonymous):

yup sorry i got to go to class! :)

OpenStudy (anonymous):

Ok thanks!

OpenStudy (debbieg):

In general, you will simplify the radical expression if you have any perfect squares under the radical. So you would be looking for a number that has a factor which is also a factor of 6. Then when you take that product, you automatically have a "perfect square" under the radical - the product of the common factors in the multiplication. If you multiply 6 x something that either (a) has a factor of 2 or 3, or (b) has a factor that is, standing alone, a perfect square - then that radical will simplify further. Otherwise, it won't.

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