Question

factorise: (x^2 + y^2 + z^2) ^ 2 - 4 x^2 y^2

Answer 1

This is what i wanted to say:-
\[(x ^{2} + y ^{2} + z ^{2})^{2} - 4x ^{2}y ^{2}\]

Answer 2

\[\left( x ^{2}+y ^{2}+z ^{2} \right)^{2}-\left( 2xy \right)^{2}\]
\[use a ^{2}-b ^{2}=\left( a+b \right)\left( a-b \right)\]

Answer 3

thnx

Answer 4

if you want complex factors then it can be factorised further.

Answer 5

i have to more questions...would u like to help me out?

Answer 6

sure

Answer 7

\[4^{x} - 3^{x-1/2} = 3^{x+1/2} - 2^{2x-1}\]
solve for x

Answer 8

sure

Answer 9

sorry openstudy crashed

Answer 10

\[\left( 2^{2} \right)^{x}-3^{x}*3^{\frac{ -1 }{2 }}=3^{x}*3^{\frac{ 1 }{2 }}-2^{2x}*2^{-1}\]

Answer 11

\[2^{2x}-\frac{ 3^{x} }{ \sqrt{3} }=\sqrt{3}*3^{x}-\frac{ 2^{2x} }{2 }\]

Answer 12

\[2^{2x}\left( 1+\frac{ 1 }{ 2 } \right)=3^{x}\left( \sqrt{3}+\frac{ 1 }{ \sqrt{3} } \right)\]

Answer 13

\[\frac{ 3 }{ 2 }2^{2x}=\frac{ 4 }{\sqrt{3} }3^{x}\]

Answer 14

\[\frac{ 2^{2x} }{ 3^{x} }=\frac{ 4 }{ \sqrt{3} }*\frac{ 2 }{3 }\]

Answer 15

\[\left( \frac{ 2 }{ \sqrt{3} } \right)^{2x}=\left( \frac{ 2 }{ \sqrt{3} } \right)^{3}\]

Answer 16

2x=3
x=3/2

Answer 17

if you want any clearification ,you can ask

Answer 18

i've understood...thnk u so much :)
last one:
if \[\sqrt{a-b} = (b/a )^{1-2x}\]
find x