Question

Can someone please help me with my prelab questions.

Write a protocol for how to prepare 100mL of a 0.50M AgNO3 solution

Answer 1

can u tell me AgNO3 molar mass

Answer 2

Its 169.875g/mol

Answer 3

The solution contains 0.1 liter \(\times\) 0.5M = _______ mol AgNO\(_3\).
Now, calculate the mass: _______ mol \(\times\) 169.873 \(\frac{g}{mol}\) = _____ g

So dilute _____ g AgNO\(_3\) in 100 ml water.

Answer 4

9g of AgNO3

Answer 5

169.873 -1000ml -1M
16.9873-100l-1M
8.5----100ml-0.5M

Answer 6

Thanks

Answer 7

yw :)